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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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  1.  
    2. Sir please do give detail solution of the Qusets as few of questions are a bit hard ....
    6 months ago by

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  2.  
    3. videos not playing
    8 months ago by Danesh Mali

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  3.  
    4. ,jlhhhhhhhhhhhhk
    9 months ago by

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  4.  
    5. Should we practice the question set when it is given or we should first watch all the lectures make notes and then solve those questions
    9 months ago by

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  5.  
    6. What is referance frame , please explain sir.
    10 months ago by

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  6.  
    7. ??
    1 years ago by Devansh Mishra

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  7.  
    8. Sir, when stone is released from balloon then once it will go up and then it will have free fall motion so we have to deal them as 2 independent situations or directly take as a one situation i am not sure with this concept please guide
    2 years ago by aryan mishra

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  8.  
    9. Sir why do we add a = 2m/s² when the observer is inside lift and doesn't consider it ?
    2 years ago by Shubham

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  9.  
    10. can I watch the lecture in 2x speed
    2 years ago by jaydev paul

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  10.  
    11. sir but at t=18 sec they will be equal, the car wouldn't haven overtaken the truck ?
    2 years ago by

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  11.  
    12. Where can I see solution of question set
    2 years ago by Sneha prajapat

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  12.  
    13. In example 1 why we Take same G In Upword Or Downword Direction
    2 years ago by Zaid Yousuf

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  13.  
    14. Sir how did you find the value of thetha
    2 years ago by

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  14.  
    15. Wonderful...a goldmine for me
    2 years ago by Karan Raj

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  15.  
    16. sir in average speed and average velocity how the time taken is t2-t1 and why we shouldn't sum it as t1+t2..
    2 years ago by Janani Jan

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  16.  
    17. where do we get the solutions for the QuSet provided above, please respons it will be really helpful
    2 years ago by

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  17.  
    18. Sir , i am kritika Mujhe yeh puchna h iss question me apne g= 10 m/s² ku liya yeh to given nii tha
    2 years ago by

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  18.  
    19. Sir, reference can also be related to earth's rotation; we move (rotate rather) alon with the earth in a rotation(day). This can also be related with the motion of a body in a bus or a car. One more point(though this point is not related) hanging in air(if possible) would take us to different countries without any motion and we could clearly see earth's movement! Though this is a query box, i just wrote these things as this box were a discussion box. THANK YOU ASHISH SIR for these videos and this opportunity.
    3 years ago by Dhruv Koli

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  19.  
    20. thank you sir!!!
    3 years ago by Dhruv Koli

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  20.  
    21. Sir, In the car example, why we take acc. of A w.r.t B = -(aA aB). according to me it should be aA aB
    3 years ago by

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  21.  
    22. screen shot size
    3 years ago by Sachin Katiyar

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  22.  
    23. Sir, the test papers which are given in between the lectures, are not containing the solutions, any source of solution of those test papers.
    3 years ago by
    Ans 1 ->
    sir pls reply i also have same question
    2 years ago by ayan sharma

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  23.  
    24. videos r once stoped cant play again it is strucking
    3 years ago by sai keerthana
    Ans 1 ->
    view on youtube
    3 years ago by Dhruv Koli

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  24.  
    25. An athlete starts running along a circular track of50 m radius at a speed 5 m/s in the clockwise direction for 40 s. Then the athlete reverses direction and runs in the anticlockwise direction at 3 m/s for 100 s. At the end, how far around the track is the runner from the starting point ?
    3 years ago by Prem Kumar
    Ans 1 ->
    Distance and displacement 500m ,100m resp.
    3 years ago by undefined

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  25.  
    26. We cannot participate in quiz again
    3 years ago by Ayush gupta

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  26.  
    27. If I assume that a car is approaching a wall with a constant velocity seperated by a distance of 500m , then the distance will be getting reduced as 100m:-) 100cm :-) 100nm :-) ......so on , i.e., the seperation is tending to zero with the passage of time . Then for the car to hit the wall , it should cross a distance which is minimum in the universe . Then what is the most minimum distance in the universe ? Please help
    3 years ago by Shahil Kumar Singh Rajput

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  27.  
    28. sir but if iam doing by the nth second displacement that is by distance = sn-sn-1 in this case= s9-s8 = 2 m/s but sir ur ans is coming 1/2 m/s and when i do the same way as u it is coming 1 /2 m/s
    3 years ago by

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  28.  
    29. Sir why 18 sec 20/2 is 10 sec
    3 years ago by

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  29.  
    30. Super
    3 years ago by

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  30.  
    31. Super
    3 years ago by

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  31.  
    32. Super
    3 years ago by

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  32.  
    33. Super
    3 years ago by

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  33.  
    34. Super
    3 years ago by

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  34.  
    35. Super
    3 years ago by

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  35.  
    36. Super
    3 years ago by

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  36.  
    37. having doubt in Q 16 of Quset -1
    3 years ago by

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  37.  
    38. what is uniform motion
    3 years ago by mohd arham
    Ans 1 ->
    if a body travels equal distances in equal intervals of time (constant velocity)
    3 years ago by

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  38.  
    39. Why not calculated time at initial velocity at 5 m/s ?
    3 years ago by

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  39.  
    40. Sir, can time should be same when we pute u=5 m/s isted of u=0 ?
    3 years ago by

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  40.  
    41. from where can we get the solutions of the QuSets which are asked in the middle of the chapter?
    3 years ago by

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  41.  
    42. sir , answer should be 9 seconds but your answer is 18 seconds , please correct it . with respect from one of your students thank you
    4 years ago by Ak singh

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  42.  
    43. the direction of velocity of seconds hand of a clock at any instant of time
    4 years ago by FDr. Yashaswini oncologist

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  43.  
    44. What is significance of negative time sir..
    4 years ago by Hritik Kumar

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  44.  
    45. these videos are not playing on the android app after login, even i reinstalled the app but are playing when i login to the physics galaxy website on windows PC. Why these videos are not working on the android app?
    4 years ago by Rohan yadav

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  45.  
    46. sir how can the relative accelerationof car A w.r.to carB can be negative of the sum of the acceleration of carA and carB.please explain me.
    4 years ago by BAMDEV BHATT

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  46.  
    47. sir!! why we tahe acceleration only be g while we are talking with net acceleration with respect to ground....
    4 years ago by Shubham Vig

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  47.  
    48. how to know the questions is rectilinear
    5 years ago by Abhishek Jadhao

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  48.  
    49. sir is all lessons are completed and is they are sufficient for iit
    5 years ago by Abhishek Jadhao

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  49.  
    50. in this how does the velocity v1 becomes negative and moves towards north
    5 years ago by karthick

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  50.  
    51. sir i want to know where to get the solutions of Qusets...i want to see their solutions...sir plse reply
    5 years ago by subham kumar sharma

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  51.  
    52. pls explain 6 graph
    5 years ago by srinjay ayan

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  52.  
    53. if Velocity of a body at an instant is zero then its acceleration should also be zero at that instant because instantaneous acceleration is given as vdv/dx where v is the velocity at any instant. so on substituting v=0 in given formula instantaneous acceleration should be zero. but why is it not so? sir pls pls help me
    5 years ago by Rupam Haloi

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  53.  
    54. a body of mass 4kg acted on by a force travels 4m in the first second and a further distance of 1m in next second.the force acting on the body is
    5 years ago by prasad telaprolu
    Ans 1 ->
    for first second 4 = u a/2 and v = u a (1) for next second 1 = v a/2 = u a a/2 (2) 1-2 3 = -a a = 3 retardation (i.e., force is opposite to initial velocity) so, force F = ma = 4(3) = 12
    5 years ago by chinchinada.manoj kumar

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  54.  
    55. Sir why don't we find the time of stone going stone in upward direction to that same point and then 100m downward and then add them all, What I had done is t1=2u/g =4sec 100=0 (1/2×10t2²) t2=_/(20) Hence total time 4 _/20 Answer is not matching please tell me where I am wrong
    5 years ago by Ritik Raj

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  55.  
    56. please upload the solution of Quset......
    5 years ago by Imranhashmi

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  56.  
    57. sir i didn't get the 5 and 6 graph in graph 5 v should be negative as slope is negative similarly i didn't get 6 graph sir please help me
    5 years ago by subhash

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  57.  
    58. Sir, why did we take S1 as U multiplied by time(.4sec)?
    5 years ago by Vishnu Deshmukh

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  58.  
    59. How to see solution of wrong ques in quese
    5 years ago by Fizza abidi

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  59.  
    60. Nice Is it sufficient to crack jee main?
    5 years ago by Fizza abidi
    Ans 1 ->
    Yes
    5 years ago by Aryab Mishra
    Ans 2 ->
    Sir.plz tell me,how can i get the solutions of ur question sets
    5 years ago by Syedsibat
    Ans 3 ->
    fizza how is your experience for lectures
    5 years ago by Abhishek Jadhao

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  60.  
    61. sir at point b given is 5 m/s but you took 2 m/s.Why?
    5 years ago by Deepak
    Ans 1 ->
    the graph is given . we need to find the solution from the graph. and it is 2 m/second square (acceleration).
    5 years ago by VARUN a

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  61.  
    62. sir please provide the solution of QuSet
    5 years ago by subhash
    Ans 1 ->
    yes sir we are not able to get the solutions of some questions in quset please provide us the solution of some hard questions
    5 years ago by Sebastian Shultz

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  62.  
    63. Very good teaching sir
    5 years ago by Aditya Pathak

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  63.  
    64. Very very helpful video sir
    5 years ago by Aditya Pathak

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  64.  
    65. Very good teaching really good teaching
    5 years ago by Aditya Pathak

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  65.  
    66. Sir i am a student of fiitjeee and sir i am in confusion as my teacher told me that third equation of motion does not give vector form and only gives magnitude and you say that all are vector equations. pls reply ASAP.
    5 years ago by Divit Goyal

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  66.  
    67. sir could you please explain last part again clearly
    5 years ago by SRI RISHITHA

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  67.  
    68. hindi lectures plz
    5 years ago by Ranjodh singh

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  68.  
    69. how can we say that motin and rest are relative terms
    5 years ago by SRI RISHITHA
    Ans 1 ->
    It depends on the frame of reference chosen....For example the same old case of sitting in a train...According to the people in the train,I am at rest whereas according to someone outside I am in a state of motion....Hope it helps
    5 years ago by ROMIT CHAKRABORTY

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  69.  
    70. how i convert language
    5 years ago by Ankit Jha

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  70.  
    71. Sir how to solve last question of the first question set? How to differenciate and wrt to whom we shud differenciate. Thank you very much sir.
    5 years ago by Sreyas Pandurang Tendulkar

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  71.  
    72. sir can u plz remove my doubt related to question no.5 in practice problems 1.1 in kinematics in physics galaxy book????why is DB length considered as L?
    5 years ago by SAUMYA SHUKLA

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  72.  
    73. Nice
    6 years ago by ABHISHEK THAKUR

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  73.  
    74. In a question in this video when two boys throw a ball in opposite direction one boy is throwing ball upward so why g is not taken negative.
    6 years ago by Ajay Kumbhar
    Ans 1 ->
    g is taken as -ve .....see acceleration of a two bodies moving towards each other is their sum of acceleration.As the acceleration of the ball thrown up is -g.....g (-g)=g-g...
    4 years ago by Goutham K

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  74.  
    75. sir please make concept videos on graph of kinematics and cover question like jee main 2018 graph question of kinematics
    6 years ago by om Gupta

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  75.  
    76. May u plse solve the last question of the video module 16 ..Mod....Without using relative motion concept. .plse
    6 years ago by Anjani Nandan Anjani Nandan

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  76.  
    77. What is uniform velocity and non- uniform velocity.
    6 years ago by Ankit raj
    Ans 1 ->
    uniform velocity means constatnt velocity
    6 years ago by gaurav samadhiya

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  77.  
    78. What is average velocity.
    6 years ago by Ankit raj
    Ans 1 ->
    Total distance covered divided by total time
    6 years ago by gaurav samadhiya
    Ans 2 ->
    Hello gaurav samadhiya bhaiya how can we get Ashish Arora sir lecture. in Hindi mix with English.
    5 years ago by Ankit raj

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  78.  
    79. A person travelling on a straight line with a uniform velocity v1 for some time and with uniform velocity v2 for the next equal time.the average velocity v is given by
    6 years ago by Ankit raj
    Ans 1 ->
    In this case average of V1 and V2
    6 years ago by gaurav samadhiya
    Ans 2 ->
    the average velocity is given by 2v1v2/v1 v2
    5 years ago by SRI RISHITHA
    Ans 3 ->
    i mean 2v1v2/v1 v2
    5 years ago by SRI RISHITHA

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  79.  
    80. Hello sir how can I get a your videos lecture in English mix with English language.sir please help me.
    6 years ago by Ankit raj

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  80.  
    81. here in an example at 7:17minutes how accelerstion becomes negative
    6 years ago by Kalyan Purimetla

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  81.  
    82. sir in the example near 12:06 minutes after reaction it will decelerates here acceleration is negative but how will the velocity be positive
    6 years ago by Kalyan Purimetla

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  82.  
    83. What would happen if at t equal to zero particles not start from origin
    6 years ago by Raushan Kumar

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  83.  
    84. sir why have you taken relative acceleration positive ?
    6 years ago by Dharamjeet Singh

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  84.  
    85. sir when we need to take reference and when not. Like you took in the example as positive x axis and negative x axis.
    6 years ago by Dharamjeet Singh

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  85.  
    86. Sir can I get all your video lecture in Hindi?
    6 years ago by rama chandra pati

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  86.  
    87. Two fixed points A and B are 20 m apart at time t=0, the distance between a third point C and A is 20 m and the distance between C and B is 10 metres the component of velocity of point C along both CA and CB at any instant is 5 metres per second. Then the distance between A and C at the instant of all three points are collinear will be?
    6 years ago by Aditya Raman

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  87.  
    88. Sir in this question ratio of distance asked and by solving we get ratio of displacement. ... Plz correct me if I am wrong.
    6 years ago by Diksha Diksha
    Ans 1 ->
    Dear friend we r assuming here motion in a straight line without changing its direction and hence distance and displacement is same
    6 years ago by Rahiab Rafiq

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  88.  
    89. Sir i am not getting (iii) of practice exercise 1.1(mehanics) from physics galaxy book..plzz upload a video on that
    6 years ago by Rahiab Rafiq

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  89.  
    90. Good
    6 years ago by DHARMENDRA PAL

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  90.  
    91. Ashish sir, from where can I get the all the booster classes videos you have mAde till now ? Actually, sir I am presently studying in a coaching institute in 12th standard so I dont much time to revise my 11 th class on daily basis.. but once my syllabus gets over , It will be required for my 11th preparation...... I hope that you will reply to me..
    6 years ago by Naman gera

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  91.  
    92. Sir in the practice questions set many pictures of questions are missing. It just shows the option. Please help sir.
    6 years ago by Pritam Das

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  92.  
    93. quset 3 ques 14 ans should be c
    6 years ago by Silla Priyadarshni

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  93.  
    94. sir if the ball goes up,the height will increase,but you wrote h=100??????
    6 years ago by Dharamjeet Singh
    Ans 1 ->
    H is not total distance it is displacement
    6 years ago by Munishwar Sharma

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  94.  
    95. i don't get answer of question 3 in quset1 plez anyone explain it
    6 years ago by Aachal Modak
    Ans 1 ->
    1st take sq root on both the side and differentiate it 2 times and then eliminate 't' , u will get the answer 'x' to power -3
    6 years ago by gaurav samadhiya
    Ans 2 ->
    but complete elimination is not possible
    6 years ago by gaurav samadhiya

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  95.  
    96. Sir, isn't time a scalar quantity, why did you represent it in the vector form. Regards
    6 years ago by Alok Shukla
    Ans 1 ->
    time is ofcourse scalar...
    6 years ago by shreyash

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  96.  
    97. Sir in 6 graph a should be negative
    6 years ago by Hardik garg

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  97.  
    98. Sir, is quset-1,2,3 problem done after completing some video?
    6 years ago by Aloke Das
    Ans 1 ->
    YES U can
    6 years ago by shreyash

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  98.  
    99. Sir this question could also be solve by using Vav=(v u)/t
    6 years ago by Hardik garg
    Ans 1 ->
    Sir but using this question in module 3 could not be solved whyy??? Pls tell sir
    6 years ago by Hardik garg

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  99.  
    100. cant we solve the collision question wrt ground frame .....adding the distances travelled by each car and applying the condition it shd be less than" d"???
    6 years ago by S Anirudh

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  100.  
    101. Sir while we are integrating why we are using limits as definite integration provides the algebraic area and in question we are asked velocity at 3m.Can't we just integrate and put 3 in obtained equation to get the velocity.
    6 years ago by Avinash Singh

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  101.  
    102. If I will follow your all lectures and advanced illustration carefully, and I will make the notes. will I able to score better in Physics. I am preparing for JEE now . I am getting very good marks in maths and chemistry , bit I am lacking that one in Physics, as Physics is also necessary for jee. so please answer me quickly, thanks.
    6 years ago by Sonu Raj

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  102.  
    103. Sir, at 0:51, you wrote Avg. velocity= (x2-x1)/(t2-t1) But, we have learnt earlier that Avg. velocity= (x1 x2 x3 x4 .......)/(t1 t2 t3t t4 ..........). Could you please explain it
    6 years ago by Sibanarayan Moharana

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  103.  
    104. Sir will the instantaneous velocity and average velocity at the peak up will be zero ???
    6 years ago by SAI
    Ans 1 ->
    yes bro
    5 years ago by prabhsimran singh

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  104.  
    105. Sir, when ball is bounced, how can it's acceleration be constant with g?? as it is opposite direction it will take -ve g right??
    6 years ago by Ravi Teja

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  105.  
    106. In first example, you have stated that ball at bottom to be rest, then how we are using relative velocity concept here?
    6 years ago by Ravi Teja

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  106.  
    107. where can i found solutions of qusets?
    6 years ago by shaad khan

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  107.  
    108. solutions for qusets please
    6 years ago by
    Ans 1 ->
    its very basic and easy questions u dont need solutions
    6 years ago by Tushar Pol

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  108.  
    109. sir in the last part of video you said the time taken to reach from position at 8 sec to position at 8.5 is same as the time taken to reach back again from 8.5 sec to 8 sec . BUT how this is possible as in 1st case velocity of both are acting in opposite direction whereas in second case accerlation was acting only in one direction so it should reach slightly away from the position at 8th second
    6 years ago by rahul jain

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  109.  
    110. A has negative acceleration so we have to add two acceleration.Explain why to subtract?
    6 years ago by Aditya

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  110.  
    111. A stone falls from rest.The total distance covered by it in the last second of its motion is equal to the distance covered by it in the first three seconds.What is the height from which the stone was dropped (A) 25m (B) 100m (C)125m (D)200m SIR WILL YO PLEASE SOLVE THIS QUESTION
    6 years ago by tarunbidaliya
    Ans 1 ->
    (c) 125
    6 years ago by nadia

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  111.  
    112. Can an object be increasing in speed as the magnitude of its acceleration decreases(please mention in both the cases of acceleration I.e. when it is negative and when positive)
    6 years ago by Avijit Jain

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  112.  
    113. sir why we are taking velocity with respect to ground as 5 m/s?
    6 years ago by Aakash

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  113.  
    114. Sir I am unable to solve this problem so plz. help me...... Q- A bird flies for 4seconds wiyth a velocity of (t-2)m/s in a straight line, where t=time in seconds. It covers a distance of... (A)2m (B)4m (C)6m (D)8m
    6 years ago by Eswar Prem

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  114.  
    115. sir i m enable to solve this pronlem so plz. help me......Q-a train of lenghth 350m starts moving rectilinearly with constant acceleration 3*10^-2 ,t=30sec . after the start the locomotive hedlight is switched om(event1) and t-60sec after the event the tail signal light is switched on (event2).Find the distance between these events in the refrence frames fixed to the train and to the earth .How and at const. velocity V relative to the earth must a certain refrences frame F move for the two events to occur in it at the same point ????? ans [242m;4.03m/s]
    6 years ago by Abhinav Tyagi

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  115.  
    116. Why the ball would take same time to come down?
    6 years ago by Rozen

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  116.  
    117. sir you taking g downward so why you not take g as -ve
    7 years ago by SAMIR MAHTO

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  117.  
    118. how can height be negative?
    7 years ago by PRACHI DEV
    Ans 1 ->
    yes u r right height is never -ve but here its not height its displacement which is -ve(as downward)
    7 years ago by Yashwant Dhote

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  118.  
    119. Sir how do we know that particle undergoes a backward motion?
    7 years ago by PRACHI DEV

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  119.  
    120. Sir the answer to the 12th question in QuSet 4 (on Motion in One Dimension) given is wrong. The answer should be a. whereas answer key given is c.
    7 years ago by Abhijith S Raj
    Ans 1 ->
    c is correct answer because velocity is changing its direction after reaching maximum height
    6 years ago by gaurav samadhiya

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  120.  
    121. Sir, the answer to the 10th question in QuSet 4 (on Motion in One Dimension) is given wrong. The answer is supposed to be 1/3 while the answer key given is 1/2. Thankyou.
    7 years ago by Abhijith S Raj
    Ans 1 ->
    1/3 is correct
    6 years ago by gaurav samadhiya

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  121.  
    122. Greeting Sir, Sir I m unable to solve this problem. Please help me. A man is standing on top of a building 100m high. He throws 2 balls vertically, one at t=0 and other after t2s. The later ball is thrown at a velocity of half the 1st. The gap between 1st and 2nd ball is 15m at t=2s. The gap remains constant. calculate their initial velocity n time interval between their throw?
    7 years ago by Sparsh Kumar

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  122.  
    123. Sir but the velocity is not acting in the backward journey so how will it take 0.5s to reach back where it was at t=8s
    7 years ago by Rajeev Gupta

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  123.  
    124. how to check velocity is positive or negative
    7 years ago by sagar

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  124.  
    125. sir why h is taken negative there
    7 years ago by sagar

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  125.  
    126. sir could you please tell how time measured changes wuth respect to reference frame
    7 years ago by ROHITH PRAKASH

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  126.  
    127. Could you please provide the solution for Q.20 QuSet2?
    7 years ago by Gautham Shankar

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  127.  
    128. why i cant just integrate and put x=3 to find distance?
    7 years ago by BHAVESH SAHU

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  128.  
    129. I found out Vel. of bolt wrt lift =4(3)^1/2 m/s. Now I used the formula of relative velocity as  Vel. Of bolt wrt lift + Vel.of lift wrt grd= Vel. Of bolt wrt grdie.  -4(3)^1/2 + 5 = 5+ 4(3)^1/2m/s  using this i got vel. Of bolt wrt grd=5-4(3)^1/2 m/s which is different from the answer 5-10/(3)^1/2 m/s....so where am I wrong and why....plz help
    7 years ago by Chetan Gupta

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  129.  
    130. Sir for the second part how cud u say that starting velocity is 20...............it has already decelerated ?
    7 years ago by Sudarshana Ghosh
    Ans 1 ->
    The question is starting when car speed is 20m/s...
    7 years ago by Physics Galaxy

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  130.  
    131. sir can't i use the limits while finding velocity and then equate to dx/dt? then it is 165m.
    7 years ago by Sudarshana Ghosh

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  131.  
    132. to find nth second distance why is Sn-Sn-1 not applicable in all cases
    7 years ago by vishnuv

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  132.  
    133. @physics galaxy the QuSet 4 has extremely large number of wrong answers pls check the answers and pls update it.
    7 years ago by soivik pal
    Ans 1 ->
    ya
    7 years ago by G Abhiram Rao
    Ans 2 ->
    Actually they are not wrong answers but they are mismatched.The answer it is showing is the answer of the next question.I guessed it through observation..
    6 years ago by PIYUSH BEHERA

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  133.  
    134. u=20 m/s g=-10 m/s h=-100 For first part of motion(Going up due to initial velocity and coming down due to gravity) Time=(2*u)/g=(2*20)/10= 4 seconds. Now for coming down v=u+at 0=20+(-10*t) 10*t=20 t=2 Therefore total time taken: 6 seconds Why is this answer not valid?
    7 years ago by Rohit Shiju
    Ans 1 ->
    The velocity at 100m is not becoming 0.so we can not apply that direct result
    7 years ago by Shah Darshan Jagdishbhai

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  134.  
    135. QuSet-4 on Motion in One Dimensions has lots of mistakes! -Needs to be looked into by the QuSet authorities
    7 years ago by PSai Krishna Kvmb
    Ans 1 ->
    Thanks we will check and if some mistakes are found, we will update it...
    7 years ago by Physics Galaxy

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  135.  
    136. IN the Collision question.AS acceleration of A and B are in Opposite directions the Shouldn't the Relative acceleration be A-B?? please Explain how it is -(A+B)
    7 years ago by Sabaresh Sabaresh
    Ans 1 ->
    As their acceleration are in opposite direction relative acceleration will be sum of the two...
    7 years ago by Physics Galaxy

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  136.  
    137. Sir, My question is from Physics Galaxy Volume 1 book, chapter 1 , interactive example 1.5 , here it is asked to find the speed of river if speed of river with respect to water remains constant , is there any printing error , or i am wrong? My another doubt in the solution of the same problem is that here it is written that , here it is written that distance travelled by raft in one hour is ukm, how it could be possible ? Please guide me , and correct me where i am wrong . Thanks !
    7 years ago by Ashish Ranjan
    Ans 1 ->
    I got the answer , this question is from i.e irodov's book question 1.1 , anyone can see the detailed explanation at https://www.youtube.com/watch?v=QfWbcq8L9SI
    7 years ago by Ashish Ranjan

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  137.  
    138. sir are these lectures are sufficient for jee mains and advance ?
    7 years ago by shweta joshi
    Ans 1 ->
    Yes... but to secure a good rank, you need to have good practice of questions based on applications of concepts...
    7 years ago by Physics Galaxy

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  138.  
    139. how can we choose that value g is 10 or 9.8
    7 years ago by vulli varsha
    Ans 1 ->
    In a given question, you need to use the value of g which is provided...
    7 years ago by Physics Galaxy

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  139.  
    140. In which case can instantaneous acceleration and average acceleration be same?
    7 years ago by vulli varsha
    Ans 1 ->
    1. if acceleration is constant or 2. in a case when direction and magnitude of average acceleration and instantaneous acceleration becomes same at some instant during mation...
    7 years ago by Physics Galaxy

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  140.  
    141. what is the difference between speed and instantaneous speed?
    7 years ago by vulli varsha
    Ans 1 ->
    speed is the term used generally for average speed if it is given for a duration... instantaneous speed is the magnitude of instantaneous velocity...
    7 years ago by Physics Galaxy

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  141.  
    142. will u please explain about how to calculate average speed?
    7 years ago by vulli varsha
    Ans 1 ->
    it is simply the ratio of total distance traveled by a body to the time taken...
    7 years ago by Physics Galaxy

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  142.  
    143. sir i am not able to access queset its submit button is not working
    7 years ago by abhishek sunda

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  143.  
    144. sir i think sir you have by mistake taken 3^3 as 9 it should be 27 isn't it??
    7 years ago by Samarth Mathur
    Ans 1 ->
    He is right as the equation was 4/3 (t)^3 when you substitute t = 3 we get 4/3 *(3^3) = 27 .
    7 years ago by Vyankatesh Muley
    Ans 2 ->
    sir took 3^3 as 27,but also it was to be divided by 3.so, 27/3 = 9
    4 years ago by

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  144.  
    145. Why in the equation a=vdv/dx,the vector sign above v, dv and dx are not given? here i am talking abt motion in 2d . and if vector sign is required 2 be given then will it be dot product or cross product pls tell how 2 wrote the eqn a=vdv/dx vectorialy(or maybe write it yourself)
    8 years ago by johnsen

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  145.  
    146. in eqn a=vdv/dx why no vector sign abv a ;v;dv and dx?
    8 years ago by johnsen
    Ans 1 ->
    Vector sign is taken when it is specified whether v is increasing or decreasing with x. if v increases with x then dv/dx is positive and if v decreases with x then dv/dx is taken -ve. This I have already explained in videos of constrained motion topic...
    8 years ago by Ashish Arora

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  146.  
    147. sir no.6 graph since the steepness is increasing therefore angle is decreasing and tanQ is also negative so how the velocity will increase ....? plzzz kindly help
    8 years ago by Yashvardhan Singh Panwar
    Ans 1 ->
    velocity always depends on the steepness. if steepness increases velocity also increases.
    7 years ago by Siobhan Mishra
    Ans 2 ->
    In the 6th graph also the velocity(magnitude) increases as steepness increases(since function of tan increases as it approaches 0)
    7 years ago by Siobhan Mishra
    Ans 3 ->
    but in negative direction(not decreasing). therefore you are mistaken that negative means decreasing.
    7 years ago by Siobhan Mishra
    Ans 4 ->
    Therefore velocity is increasing in negative direction and acceleration is in the direction of velocity(negative) since velocity is increasing. hope you get your answer.
    7 years ago by Siobhan Mishra

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  147.  
    148. Sir in example 1 of displacement-time graphs the motion of particle below the x-axis or in the negative direction is accelerated so how can it be a straight line?
    8 years ago by Yash Selot
    Ans 1 ->
    there is equal amounts of changes in velocity with time..... and change is negative sign of a number
    8 years ago by SUDHEERKUMAR VUNDI

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  148.  
    149. Sir there is a mistake in the problem of collision of two balls because the lower ball will not remain in air till 4 seconds!!!!!
    8 years ago by Ankit Kumar
    Ans 1 ->
    Yes that's true!
    8 years ago by Harsh Gupta
    Ans 2 ->
    That is why are reverting and adding it's velocity as your reference is the lower ball.
    7 years ago by Sudarshana Ghosh
    Ans 3 ->
    So what.They can collide at ground also.check the time for B to coming to the ground...
    7 years ago by Shah Darshan Jagdishbhai
    Ans 4 ->
    Sorry friends...i had made a mistake...B is not taking 4sec.
    7 years ago by Shah Darshan Jagdishbhai

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  149.  
    150. sir it should be considered as x axis or y axis. tell me sir plz
    8 years ago by surya

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  150.  
    151. if electric current has direction from positive to negative then it is considered as scalar or vector quantity and why?
    8 years ago by tarun agarwal
    Ans 1 ->
    It is scalar, since it does not follow rule of Vector addition....
    8 years ago by Krishna Raajan
    Ans 2 ->
    current is a scalar quantity but its direction still matters, so in reality it is a tensor quantity
    8 years ago by Shaleen Gupta

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  151.  
    152. why we have taken u negetive??
    8 years ago by sudeep khare

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  152.  
    153. ff
    8 years ago by Tanay Gawade
    Ans 1 ->
    plz specify??
    8 years ago by Pranay Rahul Ganji

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  153.  
    154. SIR FROM QUSET THERE ARE SOME PROBLEMS WITH THE ANSWERS. MANY OF THEM SRE WRONG IN CONTINUATION.EG.- QS16 QUES SET 4 KINEMATICS HAS WRONG ANSWER.
    8 years ago by UMANG GARG

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  154.  
    155. sir can u me for the same question how to calculate average speed
    8 years ago by srinivas
    Ans 1 ->
    (V1+V2)/2 for both velocity and speed in this case....
    8 years ago by SUDHEERKUMAR VUNDI
    Ans 2 ->
    but the method which is in this video is the good method for overall concept.
    8 years ago by SUDHEERKUMAR VUNDI
    Ans 3 ->
    can u explain how to calculate average speed?
    7 years ago by vulli varsha

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  155.  
    156. How do I find a point on s-t graph where average velocity is same as instantaneous velocity ?
    8 years ago by chitrans gupta

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  156.  
    157. Sir Im not able to acces QuSet Its showing we are sorry cannot find page--Ur loyal student
    8 years ago by Surya Prakash
    Ans 1 ->
    Thanks now the problem is fixed
    8 years ago by Surya Prakash

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  157.  
    158. 8 years ago by BISWADEEP CHAKRABORTY

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  158.  
    159. sir plz help a particle moving in a straight line with a constant acceleration.it changes its velocity from 10 ms to 20 ms while passing through a distance 135m in t secong.what is t
    8 years ago by Hritwik Pareek
    Ans 1 ->
    it is 9 sec. find it using 1st and 2nd equation of motion
    8 years ago by shashank pandey
    Ans 2 ->
    its so simple you will get 2 equations solve it answer is 9 seconds
    8 years ago by Tanay Gawade
    Ans 3 ->
    it can be solved just by 1 equation i.e. s=(v+u)t/2
    8 years ago by Meghansh Punjabi
    Ans 4 ->
    Beta your target is to find time. Now what is given in question you have initial velocity(u) as 10m/s and final velocity(v) as 20m/s and distance givengiven(s) is 135m. So let's write all euationseuations S=u×t+1/2at2 V=u+at V2=u2+2as So beta first find a from equation 3 and put it in eq2 to get your answer. Tips: Always read the question carefully Draw diagram Understand what has been asked and make that your target.
    8 years ago by Gurpreet Singh
    Ans 5 ->
    Dear Meghansh Punjabi how did you got that formulae..s=(v+u)t/2..plz ..explain
    8 years ago by Vishal Ray

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  159.  
    160. angle of tangent in v-t graph gives sign of accln. bt how to get sign of velocity? i think its very silly bt i m nt getting??
    8 years ago by Atulaya Shresth
    Ans 1 ->
    if in v-t graph velocity is above time axis then it is +ve otherwise it is -ve (following the general sign convention)
    8 years ago by chitrans gupta

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  160.  
    161. sir,practice Assignment section is not working properly. when i click on 'next question' nothing happen.
    9 years ago by rahul tiwari
    Ans 1 ->
    there is a problem in ur mouse...
    8 years ago by Pranay Rahul Ganji

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  161.  
    162. sir,in practice questions,assignment #3 question 4,is it nt A ?
    9 years ago by vishwanath v pai

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  162.  
    163. Sir in 1st e.g. when ball reaches to same height from where it is thrown then from that point how can its graph be a straight line till it reaches the ground ?
    9 years ago by APOORV

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  163.  
    164. Sir in this video you have calculated the time when the balls will collide i.e. t=4s but if we see the time of flight of ball A it comes out to be 2u/g i.e. t=1s then how can they collide at t=4s
    9 years ago by Saurabh

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  164.  
    165. a bird flies for 4 sec with a velocity mod(t-2) m/s in a straight line. how will this be presented graphically?
    9 years ago by nishita
    Ans 1 ->
    vt curve- v shaped(starting and ending at 2m/s) xt curve- cant describe it but can draw it easily
    7 years ago by Irshad Ahmed Khan

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  165.  
    166. why did we add the accelerations they are in opposite directions so the net acceleration should be 8....pls help
    9 years ago by nishita

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  166.  
    167. Sir.. if we take everything with respect to ground bolt's U=+5m/s a=-10 and s=-2........ then we get v=root 65 sir?
    9 years ago by JS.Akshaiy Ramlinkam
    Ans 1 ->
    and how can u take s=-2 wen u've considered lift as reference frame?
    9 years ago by JS.Akshaiy Ramlinkam
    Ans 2 ->
    If you are taking ground as reference frame then you cannot use s=-2 in 3rd eq. because s=-2 when we take lift as reference frame. The person at ground observes a different displacement s of bolt which can be cal. as s=5(1/root3)-1/2*g*1/3 and then you put s in 3rd eq. to get velo. final. But it is very complex procedure so you can use 1st eq. to get direct result...
    8 years ago by sudeep khare

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  167.  
    168. Can distance time graph form a triangle with x-axis? I saw it in one of the books and found it difficult to interpret. kindly help
    9 years ago by taniiiroxx
    Ans 1 ->
    At one time there can never be two positions of one particle so triangle can never be obtained above the time axis however triangle can be drawn with one side on time axis.
    9 years ago by Physics Galaxy

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  168.  
    169. Sir in this video you have calculated the time when the balls will collide i.e. t=4s but if we see the time of flight of ball A it comes out to be 2u/g i.e. t=1s then how can they collide at t=4s
    9 years ago by Saurabh

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  169.  
    170. Sir , but at t=18 seconds , is the time where car and truck meet . But not the time when car will overtake the bus . Pls!! Help . I am confused .
    9 years ago by Tejan Gupta
    Ans 1 ->
    As car is speeding up...it will overtake the truck if they are meeting...
    9 years ago by Physics Galaxy

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  170.  
    171. i wonder misconceptions or misunderstanding parts of high school physics. can you help me?
    9 years ago by adnan dever
    Ans 1 ->
    Pl ask specific questions in specific topics...
    9 years ago by Physics Galaxy

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  171.  
    172. (1)when a person leaves his home for sightseeing by his car, the meter reads 12352 km. When he returns home after two hours the reading is 12416 km, (a) what is the average speed of the car during this period? (b) what is the average velocity? (2)a car travelling at 60 km/h overtakes car travelling at 42 km/h. assuming each car to be 5.0 m long, find the time taken during the overtake and the total road distance used for the overtake.
    9 years ago by rupal malhotra

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  172.  
    173. Sir in this video you have first taken A to be at rest so why did you added the velocities of both A and B while taking relative velocity of B with respect to A because you have considered B to be at rest?
    9 years ago by Yash Selot
    Ans 1 ->
    As we are calculating vel of B with respect to A or as observed in the frame of A, we need to add velocities as these are in opposite direction and as seen by A vel of B will be vA + vB
    9 years ago by Physics Galaxy

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  173.  
    174. I have the same doubt as asked by Suhail Hakeem.
    9 years ago by Apurv Upreti
    Ans 1 ->
    g can be considered in all ref frames as body weight acts everywhere due to gravity... but in other reference frames we consider relative acceleration...
    9 years ago by Physics Galaxy

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  174.  
    175. Sir, why we consider 'g' only in frame of reference of ground?
    9 years ago by Suhail Hakeem
    Ans 1 ->
    g can be considered in all ref frames as body weight acts everywhere due to gravity... but in other reference frames we consider relative acceleration...
    9 years ago by Physics Galaxy

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  175.  
    176. A particle is released from rest from a tower of height 3h. What will be the ratio of times to fall equal heights h,i.e. T1:T2:T3 ?
    9 years ago by vaibhav sharma
    Ans 1 ->
    1:1:1
    9 years ago by harshit bansal

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  176.  
    177. A ball is dropped from a tower . In the last second of its motion it travels a distance of 15m. Find the height of the tower. [take g = 10m/sec2]
    9 years ago by Akshat Mathur
    Ans 1 ->
    20m
    9 years ago by zeenat iqbal
    Ans 2 ->
    20mts
    9 years ago by harshit bansal

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  177.  
    178. A ball is dropped from a tower . In the last second of its motion it travels a distance of 15m. Find the height of the tower. [take g = 10m/sec2]
    9 years ago by Akshat Mathur
    Ans 1 ->
    You can use speed equation to find the distance in nth second and .... Take n= sqrt (2h/g)) - 1
    9 years ago by Physics Galaxy

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  178.  
    179. A ball is dropped from a tower . In the last second of its motion it travels a distance of 15m. Find the height of the tower. [take g = 10m/sec2]
    9 years ago by Akshat Mathur

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  179.  
    180. In what time would a body acquire a velocity of 270 m/h if it was started with a velocity of 2 cm/s and moved with an acceleration of 1/2 cm/s2. find the average velocity of the body for its motion during this period
    9 years ago by Habeeba Tahaseen Banu
    Ans 1 ->
    11 seconds
    9 years ago by Kriti Agrawal
    Ans 2 ->
    time 11 sec avg velocity 4.75cm/s
    9 years ago by harshit bansal

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  180.  
    181. A particle starting from rest and moving with a uniform acceleration of 0.3 m/s2 describes in the last second of its motion 9/25 of the total distance. how long has it been in motion?
    9 years ago by Habeeba Tahaseen Banu
    Ans 1 ->
    5sec
    9 years ago by harshit bansal

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  181.  
    182. Q. A particle has an initial velocity of 9 m/s with a constant retardation of 2 m/s^2 .What will be the distance covered by the particle in fifth second?
    9 years ago by Himanshu Jale Singh Saini
    Ans 1 ->
    18m
    9 years ago by Parth Goyal

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  182.  
    183. If the acceleration of a particle is the function of distance as a = f(x). Then :- a) the velocity must be function of displacement. b) the velocity versus displacement graph cannot be a straight line. c) the velocity may be the function of displacement d) the acceleration displacement graph may be straight line. Please Give Solution
    10 years ago by Anurag Kshatri

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  183.  
    184. When acceleration be a function of velocity as a= f(v).. Then :- a) The displacement (x) = integral vdv/f(v) b) the acceleration may be constant c) the slope of acceleration versus velocity graph may may be constant. d) a) & c) are correct Please give solution
    10 years ago by Anurag Kshatri

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  184.  
    185. If the greatest admissible acceleration or retardation of a train be 3 feet/sec.sec, find the least time from one station to another at a distance of 10 meter the maximum speed be 60 mile per hour.
    10 years ago by Anurag Kshatri

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  185.  
    186. A juggler maintains four balls in motion, making each in turn rise to a height of 20m from his hand. With what velocity does he project them and where will the other three balls be at instant when the fourth one is just leaving the hand? take g=10 NOTE=SIR PLEASE GIVE SOLUTION AND ANSWER.....
    10 years ago by Arvind Bansal

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  186.  
    187. what is the distance
    10 years ago by niteesh kumar
    Ans 1 ->
    a scalar quantity always positive cannot be zero formula wise= speed * time also equal to displacement in some cases.
    10 years ago by Dr.Upendra Singh
    Ans 2 ->
    it is the length of the path covered by a particle which is independent of initial and final states of the particle where as displacement depends on the initial and final state of the particle.
    10 years ago by archana050968@gmail.com
    Ans 3 ->
    Length of path travelled
    10 years ago by manish reddy yedulla
    Ans 4 ->
    Distance is the path length traversed by the body.
    10 years ago by Dhanush K
    Ans 5 ->
    it is the length of the actual path traversed by a body between its initial and final positions.
    9 years ago by mudit
    Ans 6 ->
    The length of the actual path travelled by a particle during a given interval of time is called as distance. The distance travelled is a scalar quantity which is quite different from displacement. In general, the distance travelled between two points may not be equal to the magnitude of the displacement between the same points.
    9 years ago by Akshat Mathur
    Ans 7 ->
    Distance is the total length of the path traveled. It is a scalar quantity.
    8 years ago by Vasu Goel
    Ans 8 ->
    A SCALAR isn't that simple????
    8 years ago by Pranay Rahul Ganji
    Ans 9 ->
    distance is defined as total path length traversed
    6 years ago by erisha sayed

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