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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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  1.  
    2. sir, We are unable to see some diagrams that are drawn because of subtitles.In many videos We are facing this issue.
    3 years ago by Sailaja Pamidimukkala

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  2.  
    3. sir ,from which option of physics galaxy I shall get practice mcq
    3 years ago by Pushpendu Baidya

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  3.  
    4. Sir are these videos and illustration enough for IIT JEE ADVANCED too
    3 years ago by Harsh Dev Singh

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  4.  
    5. sir this video ended abruptly.
    4 years ago by Swapnil Aggarwal

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  5.  
    6. Sir if we do this by taking a cylinder passing though the metal surface then how we will do it?
    4 years ago by Vaasu Bisht

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  6.  
    7. sir for the cube how to do wit hsolid angle conepot give me hint im not getting it
    5 years ago by Sarju Panchal

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  7.  
    8. why did you take the cylinder horizontal?
    5 years ago by Ashutosh Manorkar

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  8.  
    9. what is the need of elf ?
    5 years ago by Chayan Majumdar

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  9.  
    10. What will be the flux due to a dipole???
    5 years ago by RAHUL GHOSH
    Ans 1 ->
    FLUX due to a dipole is zero
    2 years ago by SHRESHTHA AGARWAL

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  10.  
    11. Where should a charge Q be placed on a cube so that flux through a surface will be Q/2epsilon?
    5 years ago by Samay Sagar

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  11.  
    12. A conducting ring of radius R is given a charge Q on its surface. Find the tension produced in the ring??
    6 years ago by Gaurav Sharma

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  12.  
    13. but sir in a metal sheet electric field will be on back face also does it assume any significance with the electric field between the sheet that will be zero . regards
    6 years ago by Dhrubb gupta

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  13.  
    14. Why didn't we take a cylinderical gaussian surface?
    7 years ago by Yukti Khosla

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  14.  
    15. Sir, How does the charge on surface of sheet not used on other side of cylinder . i think it may get induced
    7 years ago by Pratyush Ranjan Roul

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  15.  
    16. Sir how come integration of xdx/(x2 L2)3/2 is done so.....................as L is a constant present in between
    7 years ago by Pratyush Ranjan Roul

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  16.  
    17. if this is a line chrge y aren't u just multiplying d efield with area.........and isn't the field 2klambda/r?
    7 years ago by Sudarshana Ghosh

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  17.  
    18. if this is a line chrge y aren't u just multiplying d efield with area.........and isn't the field 2klambda/r?
    7 years ago by Sudarshana Ghosh

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  18.  
    19. why didn't u integrate?
    7 years ago by Sudarshana Ghosh

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  19.  
    20. sir,how to draw field lines if there are more than 2 charges are present with finite distance between them ?
    7 years ago by ariya

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  20.  
    21. How can length be a vector?
    7 years ago by Rocky

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  21.  
    22. why charge on non conducting shell doesnt reside on surface?
    8 years ago by Charan Sai

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  22.  
    23. a similar question was asked in jee adv 2015
    8 years ago by Joydeep Mukherjee

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  23.  
    24. A disk of radius a/4 having a uniformly distributed charge 6C is placed in the x-y plane with its centre at (-a/2 0 0) .A rod of length a carrying a uniformly distributed charge 8C is placed on the x-axis from x=a/4 to x=5a/4.Two point charges -7C and 3C are placed at (a/4 -a/4 0) and (-3a/4 3a/4 0) respectively. Consider a cubical surface formed by six surfaces x= +- a/2 y=+-a/2 z=+-a/2.The electric flux through this cubical surface is?
    8 years ago by Kapil singh
    Ans 1 ->
    -2c/e0
    7 years ago by shubham

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  24.  
    25. Why is Gauss' Law not valid in case of dipoles? I mean to say that Electric field is present around a dipole.
    8 years ago by Shivam Agarwal
    Ans 1 ->
    if you'll apply gauss thm. to entire dipole then you'll put it inside a closed / gaussian surface and then net charge will become zero due to obvious reasons, and Gauss theorem says flux = q/ epsilon (not). since net charge is now zero therefore you won't be getting any net flux therefore we use conventional ways to find it's electric field and not the gauss thm.
    8 years ago by ANURAG KAUSHIK
    Ans 2 ->
    well try to understand gauss law it states the surface area integral is flux = q inside/e0 .here q=0 flux enclosed =0 ie every field line that start with =ve charge end in -ve charge, that surly doesnot imply E=0
    7 years ago by ANIKET

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  25.  
    26. for r=R?
    8 years ago by payal singhal

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  26.  
    27. how is the flux for abcd portion taken?
    8 years ago by payal singhal
    Ans 1 ->
    ABCD charge is given by its linear charge density * lenght So lambda * l / epsilon not
    8 years ago by Charan Sai

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  27.  
    28. is the difference taken because flux in always negative?
    8 years ago by payal singhal

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  28.  
    29. Respected Sir I am not able to find the link of solid angle. I just went through the Basic tool too then to i did not get the same. Could you please provide me the link. Anyways your videos are just awesome. Thanks
    8 years ago by deepak choudhary
    Ans 1 ->
    it is there
    7 years ago by rohit singh

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  29.  
    30. what is gauss theorem
    8 years ago by RAMU SHARMA
    Ans 1 ->
    according to gauss's law the total flux for a body is given by the charge enclosed by epsilon not.
    8 years ago by Gayatri Purigilla

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  30.  
    31. Sir could you please explain the integration in detail or tell me how to do such type of integrations??
    8 years ago by NIKHIL KUMAR MISHRA
    Ans 1 ->
    watch basic tools
    8 years ago by Charan Sai

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  31.  
    32. why is E not zero inside in this condition?
    8 years ago by utkarsh golchha

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  32.  
    33. If we keep the electric field constant and on increasing the area (say A1 to A2 where A2 is greater then A1) then it implies that phi1=EA1 is smaller than phi2=EA2. but as electric flux is the measure of electric field strength then how on increasing only the area can increase the strengh of electric field?(whenE is not changing)
    9 years ago by sudeep khare
    Ans 1 ->
    flux also depends on area as phi = EA
    8 years ago by Charan Sai

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  33.  
    34. electric flux as defined - just the no. of electric field lines passing through the given area . Then why does it has unit as V-m ? Why it is not UNITLESS ?
    9 years ago by Mohit Kuri
    Ans 1 ->
    Flux tells us about the...strength of electric field..electric field lines are jus imaginary you can't really calculate their no. ..its jus the strength
    9 years ago by joel sukumar

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