sir in Q. no. 8 of Q. set 1, we are given y in terms of x. And we are said to find (dy/dt)
when x=2.
Now my solution was,
(dy/dt) = (dy/ dx) * (dx/ dt).
(dy/dt )= (8-3x^2)* (dx/dt)
Now, when x=2, then
(dy/dt )= { 8- (3* 2^2)}* (d2/dt )
and since derivative of a constant is 0, therefore (d2/dt ) should also be equal to 0.
and therefore (dy/dt )= 0. but then the solution is given something else. Where am I wrong?
3 years ago
by
INDRA CHOUDHURY