Sir please clear my 2 doubts
1) why have you applied conservation of momentum as it can be applied only in absence of external force . Here spring force is an external force for the pan
2) after we get the velocity of the pan can we use energy conservation and write
(1/2)(3m)v^2= (1/2)kx^2-(3m)gx, where x is further compression of spring after mass m hits the pan
9 years ago
by
Mohak Sharma