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High School/JEE/NEET/IPhO Physics | 17-19 Yrs
Onion Physics for JEE & NEET
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Middle School/NTSE Physics | 14-16 Yrs
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High School/JEE/NEET/IPhO Physics | 17-19 Yrs
General Queries
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Basics of Differentiation
Basics of Integration
Basics of Vectors
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Units and Dimensions
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Motion in One Dimension
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Post your question
Sir shouldnt the work done in process AC be 60 J
5 months ago by
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amazing
2 years ago by
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In MCQ practice problems Question Set 7, question number 3 , I am not able to understand why " Work done" = PV = nRT/2 in the solution provided... Can someone please help me in this question ?. Thanks
4 years ago by Sreejan Bose
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Sorry sir its a semicircle my mistake ...
4 years ago by Akash
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Sir isn't the curve a semicircle as given in the question with radius 1..so answer is Pi(1)^2 right?
4 years ago by Akash
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Can this question be solved somehow by using the area under the curves?
5 years ago by Divy Sisodia
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work done=Q(AB) Q(BC) Q(CA)
5 years ago by
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https://youtu.be/OQ6YCQ0c1io Sir,In this video the (iii) part I am calculating work done=Q(ab) Q(BC) Q(CA) and?U=O but answer is not coming.
5 years ago by
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please provide system for speed like 2x
5 years ago by ram
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how can we transfer heat from low temp region in refrigerator
5 years ago by Jasper Bhardwaj
Ans 1 ->
The crux over here is that we are taking heat from that low temperature body by doing some external work on the refrigerator system....A body at low temperature doesn't mean that it has no heat at all....IT HAS HEAT AS LESS AMOUNT...That's the thing to be understood first...An yeah one imp thing as well we are considering input for this system as external work to be done and the output is the heat taken from the low temperature body.....
3 years ago by
undefined
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Awesome explanation
5 years ago by BELIEVE BECOME Pankaj
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Sir in V vs P graphs, unlike the P vs V graphs, the sign of clockwise work will be negative, and that for counterclockwise be positive, right?
5 years ago by Kruthik Pimpre
Ans 1 ->
No. Clockwise and anticlockwise remains same if you view it that way only changes if you view from behind the graph. I would suggest that you shouldn't just remember this like a convention. Understand the logic and use it in every case (find the net area with the volume axis)
5 years ago by
Ameya Marakarkandy
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If delta v =0 but dv is not equal to zero ,then will the process be called isochloric?
6 years ago by Harshit paddar
Ans 1 ->
No it is not an isochoric process this article was particularly emphasised by ashish sir that delv is not necessarily an isochoric process because in an isochoric process work done by the system is equal to zero hence all the heat provided to a system will only change the internal energy of the system but if dv is non zero there will be a work done by the system I hope you got the answer :)
4 years ago by
Ishaan Agarwal
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sir if the piston moves up by gas molecules than how can we say that a vacuum is created for an instance in the container ?
6 years ago by Jatin Kr
Ans 1 ->
See in the initial state the part above the piston is COMPLETELY EVACUATED...And clearly notice the thing said by sir in this video.....see when u move the piston u might imagine that gas might expand... But, THINK how it expands...So for that initially the vaccum space is created and the gas particles fill in that space.. So, that's why there is an expansion in the volume as well as decrease in the density of the gas.....
3 years ago by
undefined
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sir if work done is zero then PdV should be zero hence change in volume should also be zero so how is it doubled
6 years ago by Hardik Jadwani
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Can anyone tell me where is the content when entropy is defined by sir?
6 years ago by neeraj chatterjee
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Are students provided with a log table in the examination hall for these calculations?
6 years ago by Saurabh Raj
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A 1kg bar of copper heated at 1.01×10^5 atm from 20deg C to 50 degrees C calculate change in internal energy alpha =7.0×10^-6per °C and p =8.92*10^3kg/m^3 c =387 J/kg-°C
6 years ago by undefined
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Respected Sir, Plz Give me answer to the following question Kindly, Q.) Describing a system in which the entropy is decreasing. Is this system isolated from its surroundings?
6 years ago by Naveen Varikuti
Ans 1 ->
if the gaseous system present inside a thermally conducting container it increases the internal energy of the house....As such it increases the temperature of the gas......And ENTROPY Means degree of Randomness.....So in this system the randomness of gaseous particle increases.....
3 years ago by
undefined
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Sir where can i find the recorded versions/ live booster classes in a sequence?
6 years ago by Lalith
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sir , as we have relation for U =n Cv T but not same for U = n Cp T then how can we relate same for Cp ev as for Cv eq
7 years ago by smw
Ans 1 ->
same doubt as above
5 years ago by
amansonkar
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sir please upload the booster classes too. else share a link where we can watch it.I searched it on google but couldnt find it. Without it my preparation is incomplete.
7 years ago by sandeep Neemkar
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Sir Could you please post higher level vedios of Irodov concepts and fundamentals.....It would be really helpful
7 years ago by
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but you have took it positive
7 years ago by anita singh
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work done on atmosphere should be negative as atmosphere is compressed
7 years ago by anita singh
Ans 1 ->
The work done is considered with respect to system that is why it is taken ' ve'
7 years ago by
Manoj Jajoria
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Sir is there any process in which only one co-ordinate changes (say T)?
7 years ago by ayush raj
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a poly tropic process can be described as
7 years ago by Vidya Prakash
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Delta u written here is ncvdt ..is it xorrect or it will be ncpdt
8 years ago by Tushar Bachchan
Ans 1 ->
yes it is correct ,as change in internal energy comes by making the volume constant,so we have to use nCvdT=dU
7 years ago by
Vidya Prakash
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sir why there is a difference in the signs in physics and chemistry
8 years ago by hulk iron
Ans 1 ->
Good Question!! In Chemistery: IUPAC gave sign convention acc. to which work done by system(Expansion Vf>Vi) is -(ve) and vice versa. And accordingly they have equation as dU=q w
7 years ago by
ayush raj
Ans 2 ->
dU=q w reason is when work is done on system internal energy of system increases. So that's only a different way of writing same thing with different concern.
7 years ago by
ayush raj
Ans 3 ->
TO SHOW THE UNIQUENESS....To show their different way of thinking....Simple
3 years ago by
undefined
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Sir please explain why WORK is path function
8 years ago by Venkata Reddy
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it depends on the path followed by
7 years ago by
Akshit Gupta
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calculation of area is wrong. in the pressure coordinate the calculation shud gave 7-2=5...
9 years ago by Sharath Chandar Devendran
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Sir number of moles =2 and Cp-Cv=nR then why Cp-Cv=r only it should be 2R
9 years ago by Rajesh gupta
Ans 1 ->
Cp-Cv is always equal to R. Irrespective of moles taken.
9 years ago by
ADITYA MANTRI
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SIR why does the word done by gas depend on external pressure?
9 years ago by jeevan99
Ans 1 ->
WORD = WORK
9 years ago by
jeevan99
Ans 2 ->
Because force depends on External Pressure. and in turn work depends on force.
9 years ago by
ADITYA MANTRI
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I think calculation of area is wrong!
9 years ago by Satvik Sr
Ans 1 ->
i guess thats alright
9 years ago by
Tarun Sai
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An ideal gas has molar heat capacity Cv at constant volume. The gas undergo the process T=To(1-aV) where a, To is constant and V is volume. Then molar heat capacity of the gas is options are: (a) Cv + R(1-aV)/aV (B) Cv - R(1-aV)/aV (c) Cv - R(1+aV)/2aV (d) Cv + R(1+aV)/2aV
10 years ago by taniiiroxx
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Wouldn't it be easier to just calculate change in internal energy for Point A and Point C. And seperatly calculate total work done in processes ABC and ADC by area under curve. Then find out heat.
10 years ago by Tanay Sharma
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sir if the curve is a semi circle (as written in question) then why we are calculating area of ellipse?
10 years ago by vishal
Ans 1 ->
Dude...no need of finding area if ellipse ....as,area of semicircle is pie r square/2 and r =1
10 years ago by
lalabhai
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sir i one question which ihad can't solved A sample of an ideal gas is taken through cyclic process abca. it absorbs 50J of heat during the part ab ,no heat during bc and rejects 70J of heat during ca 40J of work is done on the gas during part bc. Find the internal energy of gas at b and c if it is 1500J at a.
10 years ago by Tushar Sinha
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What is the specific purpose of the third law of thermodynamics?
10 years ago by Ch Vishal
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