Physics Video Lecture
Connecting Students in 221 Countries
 Topic List
 Topic Modules

Video Lectures

Video Lecture Advance Illustration My Sequence My Bookmark

High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Simple Harmonic Motion
Introduction-to-Oscillations
Duration: 13.12 Min
 
Add to my sequences
Bookmark This Video
Simple-Harmonic-Motion
Duration: 6.04 Min
 
Add to my sequences
Bookmark This Video
Representation-of-SHM
Duration: 4.48 Min
 
Add to my sequences
Bookmark This Video
General-Equation-of-SHM
Duration: 8.14 Min
 
Add to my sequences
Bookmark This Video
 
Add to my sequences
Bookmark This Video
Solved-Example-1
Duration: 2.12 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-2
Duration: 1.40 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-3
Duration: 2.14 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-4
Duration: 2.13 Min
 
Add to my sequences
Bookmark This Video
Energy-of-a-Particle-in-SHM
Duration: 11.22 Min
 
Add to my sequences
Bookmark This Video
Variation-of-Energy-of-a-Particle-in-SHM
Duration: 4.37 Min
 
Add to my sequences
Bookmark This Video
 
Add to my sequences
Bookmark This Video
Time-Period-of-SHM-of-a-Simple-Pendulum
Duration: 10.57 Min
 
Add to my sequences
Bookmark This Video
 
Add to my sequences
Bookmark This Video
Angular-SHM-and-its-Equation
Duration: 7.21 Min
 
Add to my sequences
Bookmark This Video
Time-Period-of-a-Torsional-Pendulum
Duration: 3.02 Min
 
Add to my sequences
Bookmark This Video
Compound-Pendulum
Duration: 8.10 Min
 
Add to my sequences
Bookmark This Video
Equivalent-Length-of-a-Simple-Pendulum
Duration: 11.30 Min
 
Add to my sequences
Bookmark This Video
 
Add to my sequences
Bookmark This Video
Energy-of-Oscillation-in-Angular-SHM
Duration: 5.04 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-5
Module - 21 Solved Example-5
Duration: 3.30 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-6
Module - 22 Solved Example-6
Duration: 2.55 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-7
Module - 23 Solved Example-7
Duration: 1.45 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-8
Module - 24 Solved Example-8
Duration: 3.04 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-9
Module - 25 Solved Example-9
Duration: 3.00 Min
 
Add to my sequences
Bookmark This Video
Cases-of-Spring-Combinations-in-SHM
Duration: 7.20 Min
 
Add to my sequences
Bookmark This Video
Effect-of-Constant-External-Force-on-SHM
Duration: 8.36 Min
 
Add to my sequences
Bookmark This Video
Energy-Method-to-find-Frequency-of-SHM
Duration: 8.56 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-10
Duration: 3.34 Min
 
Add to my sequences
Bookmark This Video
Solved-Example-11
Duration: 5.01 Min
 
Add to my sequences
Bookmark This Video
 
Add to my sequences
Bookmark This Video
  1.  
    2. Sir I did not understand how did you write A and B as Rcos(phi) and Rsin(phi)?
    4 years ago by M.V.S.S KARTHIK

    Post your answer here

  2.  
    3. Sir I did not understand how did you write the values of A and B as Rcos(phi) and Rsin(phi)?
    4 years ago by M.V.S.S KARTHIK

    Post your answer here

  3.  
    4. thanks for your efforts.this is the true nationalism.
    5 years ago by ABHISHEK MISHRA

    Post your answer here

  4.  
    5. sir, is it correct to judge the amplitude directly since max value of y=Asin(x) Bcos(x) will be root of (A^2 B^2)?
    7 years ago by Ashwin Murali
    Ans 1 ->
    sorry,root of (A^2 B^2)
    7 years ago by Ashwin Murali

    Post your answer here

  5.  
    6. sir can we substitute any other constants for A and B?
    8 years ago by saikiran

    Post your answer here

  6.  
    7. Sir but why have you exactly substituded A and B as function of theta
    9 years ago by Mohak Sharma
    Ans 1 ->
    Here R and phi/theta are both constants and A and B are also constants so I have just defined a relation among constants with which we are able to transform the given equation in the known form of equation of SHM... thats it...
    9 years ago by Physics Galaxy

    Post your answer here

  7.  
    8. how can you say that both A and B are function of theta
    10 years ago by manish reddy yedulla
    Ans 1 ->
    please reply
    10 years ago by manish
    Ans 2 ->
    A and B are constants and any two constants can always be expressed in terms of two other constants... which we have done here to reduce the given function in the form of SHM...
    9 years ago by Physics Galaxy
    Ans 3 ->
    Test Content
    8 years ago by Anushree Wasule

    Post your answer here

QUICK LINKS
FEATURES
INFO
SITEMAP & POLICIES