Sir, My Self is LALA KARTHIK.Sir, in this lecture the equation (1) is wrong..sir.instead of, + u should keep (-) sign sir..
9 years ago
by
lalabhai
Ans
1
->
Equation (1) is correct as due to work done by gravity so work done by gravity is added to initial kinetic energy...
9 years ago
by
Physics Galaxy
Ans
2
->
#lala .. the eq 1 is crrect but it sdervtn is wrng !it should be 1/2mu^2 + mgR(1-cos(theta))=1/2mv^2. .. !
8 years ago
by
vishwanath v pai
Ans
3
->
Yes sir it should be 1/2mu^2 + mgR(1-cos(theta)) =1/2mv^2 ....... because the work done is done in direction of displacement..
Sir plz.. look after this and reply soon..
8 years ago
by
Vishal Ray