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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Basics of Integration
Duration: 8.07 Min
 
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Duration: 10.18 Min
 
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Duration: 13.49 Min
 
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Duration: 12.50 Min
 
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Duration: 6.31 Min
 
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Duration: 8.17 Min
 
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Duration: 3.09 Min
 
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Duration: 3.23 Min
 
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Duration: 3.21 Min
 
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Module - 10 Volume of a Cone
Duration: 3.15 Min
 
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Duration: 3.17 Min
 
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  1.  
  2. good
    1 years ago by Sajal Z

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  3.  
  4. sir could u please share solution of integrate i/x^2 .e^1/x dx using e^1/x =t
    3 years ago by Rahul Manjunath Harlapur

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  5.  
  6. in the video integration by substitution at 9 . 30 e to the power 4x became t ......... how?
    4 years ago by

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  7.  
  8. very helpful videos Sir, just a suggestion : When we pause the video a box appears containing more videos which block the view from the Question / Video which is not needed.
    6 years ago by Aaniranjan Saraf

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  9.  
  10. Very good teaching method!
    6 years ago by Durvesh Rajan Dambe

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  11.  
  12. Is there any other method of solving the last example I took t=cosx And got cos4/4-cos^6/6=sin³/3-sin^5/5
    6 years ago by Tanmay Goyal

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  13.  
  14. what is diffrentiation of e^1/x?
    6 years ago by Krishna Gupta
    Ans 1 ->
    -e^1/x/x^2
    6 years ago by abha sachan

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  15.  
  16. Sir I think that instead of ln cosx there must be ln |cosx | as cos x can't be negative.
    7 years ago by SSK

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  17.  
  18. Sir why did you took cos^3 x as (1-t^2)dt?
    9 years ago by Yash Selot
    Ans 1 ->
    dt=cosxdx, and cos^3x can be written as cos^2x.cosx. so cosx was consumed by dt and cos^2x can be wriiten as (1-sin^2x). t is equal to sin x so the value of sin^2x will be t^2. so cos^2x became (1-t^2). thats how cos^3x became (1-t^2)dt
    6 years ago by Rudransh Tyagi

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