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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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In previous example too the boy was at rest initially before he jumped and hence his angular momentum was taken as zero.But in this example he starts walking from rest but his initial angular momentum is taken as MR^2. Could you please explain.

9 years ago by Ritwik Jha

Ans 1 ->

In the previous example initially the platform and the boy as a system were at rest...recall that the platform recoiled with an angular velocity w(omega)...in order to conserve the angular momentum after the jump of the boy....so the initial angular momentum was '0' in that case..But in this case the platform is already rotating with an initial angular velocity w1...so it will have initial angular momentum...Hope It Helps!!!

8 years ago by shreya sood

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sir, kindly tell me why while calculating Lf,why did we minus it and why not we added it as we did in the previous problems?

10 years ago by Vineet Chatterjee

Ans 1 ->

mad dont know this much also analyse it u will get it

9 years ago by mukhtar

Ans 2 ->

As boy is walkingAs boy is walking in opposite direction... his speed with respect to ground will be u - Rw2 and we use conservation of angular momentum in the frame of ground...

9 years ago by Physics Galaxy

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in solved eg. 12 of rigid body mechanics, won't the L(final) be Iw2-m(u+Rw2)R??

10 years ago by Balaji Aathithan

Ans 1 ->

NO. As boy is walking in opposite direction... his speed with respect to ground will be u - Rw2 and we use conservation of angular momentum in the frame of ground...

9 years ago by Physics Galaxy

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Video Lectures

High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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