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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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Sir in the last equation of forces "2mg N = m(v1)^2/R" shouldn't we take 2v1 instead of v1 as at the uppermost point the velocity of mass will be (velocity of com) (wr) and as it is pure rolling both are equal hence the velocity at topmost point should be 2v1.

6 years ago by undefined

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How can we assure that minimum normal will be when small mass is at the top. it is clear that it will be in the upper half. Potential energy of system is increasing and kinetic energy is decreasing as it is going up. my doubt is two things happening simultaneously velocity of ring is decreasing and centrifugal force is becoming more and more vertical

9 years ago by AKASH GOYAL

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When the mass is not at the top or in upward motion on top... the centrifugal force will be in outward direction and passing through the bottom contact as it is instantaneous aor... only its upward component of this force will reduce the normal reaction which will be min when it reaches the top... analytically you can calculate and prove it also...

9 years ago by Physics Galaxy

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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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