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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Relative Motion
Duration: 8.48 Min
 
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Duration: 1.29 Min
 
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Duration: 2.21 Min
 
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Duration: 2.27 Min
 
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Duration: 16.52 Min
 
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Duration: 2.39 Min
 
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Duration: 2.59 Min
 
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Duration: 3.50 Min
 
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Duration: 3.57 Min
 
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Module - 10 Rain Fall Cases
Duration: 6.54 Min
 
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Module - 11 Solved Example-8
Duration: 2.36 Min
 
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Module - 12 Solved Example-9
Duration: 1.48 Min
 
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Duration: 2.34 Min
 
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Duration: 5.59 Min
 
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Duration: 2.29 Min
 
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Duration: 2.51 Min
 
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Duration: 3.07 Min
 
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  1.  
  2. Can we don't solve the question set? If yes then how because it is going to open the video in YouTube.
    5 years ago by

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  3.  
  4. isnt the distance covered by a in that time 2d?
    6 years ago by Aatreya Kapoor

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  5.  
  6. i think in the second last step it should be => 3d=5 * d/Vb - 10
    7 years ago by SAI
    Ans 1 ->
    no it should be d because they are originally at a separation 2d and then in that time t A covered a distance d
    6 years ago by aaditya chaturmohta

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  7.  
  8. How did he caluculate Vbc
    8 years ago by aiswarya rallapalli

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  9.  
  10. D/Vb-10 is d common time .... but how does he know dat it travels d units in dis time period
    8 years ago by aiswarya rallapalli
    Ans 1 ->
    Well thats wat d question is
    8 years ago by aiswarya rallapalli

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  11.  
  12. why +5 is considered apart from -5 in the last expression.. as relative velocity of A wrt C is -5..please help!!!
    8 years ago by shreya sood
    Ans 1 ->
    its seems like a silly mistake please consider that to be -5
    6 years ago by Rajesh kumar yadav

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  13.  
  14. sir but answer comes out to be 25m/s as its d/3 = 5 * (d/vb-10)
    9 years ago by Abhisek Sahoo
    Ans 1 ->
    the distance walked by A is 3d-2d=d therefore the equation is correct
    8 years ago by Mohammad Shehzaad

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