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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Geometrical Optics I - Reflection of Light
Duration: 4.22 Min
 
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Duration: 2.32 Min
 
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Duration: 2.29 Min
 
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Duration: 2.51 Min
 
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Duration: 2.47 Min
 
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Module - 8 Plane Mirrors
Duration: 3.23 Min
 
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Duration: 6.11 Min
 
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Duration: 3.02 Min
 
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Module - 18 Solved Example-1
Duration: 2.46 Min
 
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Module - 19 Solved Example-2
Duration: 2.18 Min
 
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Module - 20 Solved Example-3
Duration: 1.48 Min
 
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Module - 21 Solved Example-4
Duration: 2.27 Min
 
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Module - 22 Solved Example-5
Duration: 2.51 Min
 
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Module - 23 Solved Example-6
Duration: 3.15 Min
 
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Duration: 4.54 Min
 
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Duration: 4.37 Min
 
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Duration: 7.57 Min
 
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Duration: 5.30 Min
 
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Module - 33 Solved Example-7
Duration: 3.24 Min
 
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Module - 34 Solved Example-8
Duration: 3.57 Min
 
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Module - 35 Solved Example-9
Duration: 3.15 Min
 
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Duration: 2.50 Min
 
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Duration: 2.29 Min
 
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Duration: 5.13 Min
 
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  1.  
  2. Why we don't use the concept of module 12, which is "minimum length of mirror required to see self-image". what happens when we switch the self-image to the size of the wall i.e. 3m. hope you understand what i am saying.
    4 years ago by Ishan Dhamija

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  3.  
  4. Sir, I didn't get how you applied the similarity? Which two triangles are similar here?
    7 years ago by Harish D

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  5.  
  6. sir could you please explain which two triangles are similar and the parameters of similarity ?
    9 years ago by Kaushik Govindharajan
    Ans 1 ->
    Triangle EAB and EA'B' Base-Altitude
    8 years ago by Irshad Ahmed Khan

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  7.  
  8. sir can u pls explain how by similarity of triangles we have arrived to h/5=3/25 i tried a lot but was unable
    10 years ago by vishal
    Ans 1 ->
    For Triangles to be similar, They should have: 1)their corresponding angles equal or 2)Corresponding sides will have same ratio. So, here, all the corresponding angles are equal. So, they are similar. After finding the similarity of these triangles, we can use the expression: h/5=3/25
    10 years ago by Sabbarish Govindarajan

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