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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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can you explain me how to determine that the result would come through(2nd aproach) ucosø=v(b) or u=v(b) cosø are both the cases true or not(please provide the reason of why or why won't we take any of the result)

1 years ago by Shashwat

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In the alternative method can we break components of "u" as ucos(theta) = Vb

4 years ago by

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method 1 is better

4 years ago by

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sir pls tell in alternate method where you have written vbcostheta there should beVb and where you have written vb there should be vbcostheta because motion is due to the string

5 years ago by Yash Veer Nagar

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sir in the alt.method how does the length remain constant when the separation between the boat and boy is decreasing

7 years ago by gurpreet kour

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sir i also have the same doubt

6 years ago by subhash

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sir you have resolved Vb and not U if we resolve U then ans comes Ucos (theta)=Vb. How to undersand what to resolve

8 years ago by Poonam Jain

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we can only resolve the actual speeds not the speed with which body is not actually moving...

7 years ago by Physics Galaxy

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1.In the alternative method the concept that the string have a constant lenth while the boy is pulling it?

9 years ago by Aryan Malguri

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sir,how you breaked the component of velocity of boat.it's not satisfying pythagorus theorem. and thanks 4 all lectures it worth a lot.

9 years ago by Amit

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Video Lectures

High School/JEE/NEET/IPhO Physics | 17-19 Yrs

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