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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Rigid Body Dynamics
Duration: 5.17 Min
 
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Duration: 7.49 Min
 
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Duration: 1.31 Min
 
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Duration: 3.50 Min
 
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Duration: 5.16 Min
 
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Duration: 3.36 Min
 
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Duration: 4.41 Min
 
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Duration: 4.13 Min
 
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Duration: 4.31 Min
 
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Duration: 16.34 Min
 
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Duration: 14.42 Min
 
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Duration: 4.05 Min
 
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Module - 13 Solved Example-1
Duration: 1.55 Min
 
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Module - 14 Solved Example-2
Duration: 3.29 Min
 
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Module - 15 Solved Example-3
Duration: 4.31 Min
 
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Module - 16 Solved Example-4
Duration: 2.15 Min
 
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Duration: 9.58 Min
 
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Module - 18 Solved Example-5
Duration: 2.47 Min
 
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Module - 19 Solved Example-6
Duration: 5.07 Min
 
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Module - 20 Solved Example-7
Duration: 4.44 Min
 
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Module - 21 Solved Example-8
Duration: 2.21 Min
 
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Module - 22 Solved Example-9
Duration: 3.28 Min
 
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Module - 23 Angular Momentum
Duration: 17.59 Min
 
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Duration: 7.25 Min
 
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Duration: 2.37 Min
 
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Duration: 2.53 Min
 
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Duration: 3.25 Min
 
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Duration: 2.35 Min
 
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Duration: 10.39 Min
 
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Module - 32 Solved Example14
Duration: 7.32 Min
 
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Module - 33 Solved Example15
Duration: 4.03 Min
 
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Module - 34 Solved Example16
Duration: 4.49 Min
 
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Module - 35 Solved Example17
Duration: 4.48 Min
 
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Module - 36 Solved Example18
Duration: 4.40 Min
 
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Duration: 11.41 Min
 
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Module - 38 Solved Example19
Duration: 2.24 Min
 
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Module - 39 Solved Example20
Duration: 4.45 Min
 
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Duration: 7.53 Min
 
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Duration: 3.36 Min
 
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Duration: 4.51 Min
 
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  1.  
  2. sir why cant i do like this as MI of disk is 1/2mr^2 so of half dik it would be 1/4mr^2 (because MI is additive) now as some portion is cut so mi should be=1/4m(R1^2-R2^2) . as i can subtract moment of inertia of cutted disk
    9 years ago by Dheeraj Agarwal

    Post your answer here

  3.  
  4. what is the moment of inertia of half disc about its c.o.m perpendicular to plane
    10 years ago by rohit pandey
    Ans 1 ->
    You can calculate it using parallel axis theorem... using Ic = I(about central axis) - M(4R/3pi)^2 where I(about central axis) = 0.5MR^2
    10 years ago by Physics Galaxy

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